3x=128^(3/5)-5

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Solution for 3x=128^(3/5)-5 equation: 



3x=128^(3/5)-5

We move all terms to the left:

3x-(128^(3/5)-5)=0

We add all the numbers together, and all the variables

3x-(128^(+3/5)-5)=0

We multiply all the terms by the denominator


3x*5)-5)-(128^(+3=0

Wy multiply elements

15x^2+3=0

a = 15; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·15·3
Δ = -180
Delta is less than zero, so there is no solution for the equation

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